The latent heat of vaporization of water is 540 calories/gram. How many calories are required to completely vaporize 500 grams of water?

use the heat of vaporization

1gram = 540calories

how many calories when 500g is vaporized?

To calculate the total calories required to completely vaporize 500 grams of water, you can use the formula:

Total calories = Latent heat of vaporization x Mass

Given that the latent heat of vaporization of water is 540 calories/gram and the mass is 500 grams, we can substitute these values into the formula:

Total calories = 540 calories/gram x 500 grams

Total calories = 270,000 calories

Therefore, 270,000 calories are required to completely vaporize 500 grams of water.

To find out how many calories are required to completely vaporize 500 grams of water, you need to multiply the mass of water by the latent heat of vaporization.

The formula is:
Energy = Mass x Latent heat of vaporization

In this case, the mass of water is 500 grams and the latent heat of vaporization is 540 calories/gram.

So, to calculate the energy required to vaporize 500 grams of water:
Energy = 500 grams x 540 calories/gram

Now, let's do the math:
Energy = 270,000 calories.

Therefore, 270,000 calories are required to completely vaporize 500 grams of water.