Find the integral of sin(x) cos(x)/sin^2(x)-4 dx
sin(x) cos(x)/(sin^2(x)-4) =
-sin(x) cos(x)/(cos^2(x) + 3)
-sin(x) is the derivative of cos(x), therefore,
so d(cos(x)) = -sin(x) dx
Integral of
-sin(x) cos(x)/(cos^2(x) + 3) dx =
Integral of
cos(x)/(cos^2(x) + 3) dcos(x) =
Integral of u/(u^2+3) du =
1/2 Integral of 2u/(u^2+3) du =
1/2 Log(u^2+3) =
1/2 Log[cos^2(x) + 3]