Math for Educators
posted by Carol .
Find the 9th term of sequence.
4, 12, 36, 108, ....
The 9th term of sequence is ??
My answer 236,196
4+[3(n1)]
Correct?

Looks like Tn = 4*3^(n1)
So, T9 = 4*3^8 = 26244
4,12,36,108,324,972,2916,8748,26244,...
With your proposed sequence 4+3(n1) how did you get such a large number?