In the movie Spiderman 2, there's a famous minute long scene where Spiderman stops a train. If the initial speed of a five car out of control subway train was around the top speed of the NYC subway (27 m/s), and Spiderman stopped the train in exactly one minute, then what is the magnitude of the force in Newtons that Spiderman exerted on the train as he stopped it?

Details and assumptions
A standard New York City subway car full of terrified passengers has a mass of roughly 40,000 kg.
You may assume the acceleration was constant and any other forces are negligible.

90000

To determine the magnitude of the force that Spiderman exerted on the train, we need to use Newton's second law of motion, which states that force is equal to mass multiplied by acceleration.

First, let's calculate the acceleration of the train using the given information. The train initially has a speed of 27 m/s and comes to a stop in 60 seconds (1 minute). To calculate the acceleration, we need to find the change in velocity.

Δv = vf - vi
Δv = 0 - 27
Δv = -27 m/s (negative sign indicates the change is in the opposite direction)

Next, we can use the equation for acceleration.

acceleration = Δv / t
acceleration = -27 m/s / 60 s
acceleration = -0.45 m/s^2 (negative sign indicates deceleration)

Now, we can calculate the force exerted by Spiderman on the train.

force = mass x acceleration
force = 40,000 kg x (-0.45 m/s^2)
force ≈ -18,000 N (negative sign indicates the force is in the opposite direction)

Therefore, the magnitude of the force that Spiderman exerted on the train as he stopped it is approximately 18,000 Newtons.