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October 26, 2014

October 26, 2014

Posted by **Leo** on Tuesday, June 4, 2013 at 1:26am.

- Math -
**MathMate**, Tuesday, June 4, 2013 at 6:45amLet O = centre of circle Γ, then

∠PAO=90°

- Math -
**MathMate**, Tuesday, June 4, 2013 at 6:49amLet O = centre of circle Γ, then

∠PAO=90°

Consider ΔPAC,

use sine rule to find ∠PAC, which

equals 13° (approx.).

∠CAO is therefore 90-∠PAC and equals 77° approx.

Since Δ CAO is isosceles, with congruent legs equal to the radius r of the circle Γ, and base length = 16, r can be solved.

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