Math
posted by Mathslover on .
Find the smallest number N such that:
The number of divisors of N is A.
The number of divisors of A is B.
The number of divisors of B is C.
The number of divisors of C is 3.
Details and assumptions
The divisors include 1 and the number itself. For example, the number of divisors of 10 is 4.

I have one feasible solution, not sure if it is optimal. You can find others for a check along the same lines.
C=4, 3 factors: 1,2,4
B=6, 4 factors: 1,2,3,6
A=12,6 factors: 1,2,3,4,6,12
N=72,12 factors: 1,2,3,4,6,8,9,12,18,24,36,72 
its wrong

This is your last warning, mathslover. We have been able to pinpoint your brilliant account, and if you keep on posting Brilliant questions here your account will be terminated.
Calvin Lin
Brilliant Maths Challenge Master