algebra 1
posted by karina c .
Inequality 3  2x2  +16<58
•simplify as much as possible without moving the absolute value sign
•rewrite the inequality as two inequalities with out absolute value signs• find solution set of the inequality and graph solution set on a number line

subtract 16 from each side, then divide each side by 3
abs(2x2)<14
what if 2x2<14, then x<8
what if (2x2)<14, then
2x+4<14
2x<10
x>5 
0.08x+2.1=