The velocity of a vehicle is uniformly reduced from 72km/h to 24km/ over a distance of 250m down a decline of 1:25 the mass of the vehicle is 1.5Mg and its tractive resistance is 400N. The retardation is uniform. Calculate the total constant braking force required
so I found the deceleration
v^2 = u^2 +2as
(6.667)^2=(20)^2+2a(250)
44.44=400+500a
a= -0.71111 m.s^2
but What I want to know is when calculating the forces
Braking force + tractive resistance = 1500kg x (-0.711111)
should I include the gravitational force of the vehicle?
1500sin(2.29)