A Ne-O2 gas mixture contain 76.6 g O2 and 167.5 g Ne(20).If P of mixture is 25 bar.what is partial pressure of O2 and Ne?
To determine the partial pressures of O2 and Ne in the gas mixture, we need to first calculate the number of moles of each gas present.
The molar mass of O2 is 32 g/mol, so the number of moles of O2 can be calculated as follows:
Number of moles of O2 = Mass of O2 / Molar mass of O2
= 76.6 g / 32 g/mol
= 2.39 mol
The molar mass of Ne is 20 g/mol, so the number of moles of Ne can be calculated as follows:
Number of moles of Ne = Mass of Ne / Molar mass of Ne
= 167.5 g / 20 g/mol
= 8.38 mol
Now that we have the number of moles of O2 and Ne, we can calculate their partial pressures using Dalton's Law of Partial Pressures, which states that the total pressure of a gas mixture is the sum of the partial pressures of its components.
Partial pressure of O2 = (Number of moles of O2 / Total number of moles) * Total pressure
= (2.39 mol / (2.39 mol + 8.38 mol)) * 25 bar
= (2.39 mol / 10.77 mol) * 25 bar
= 5.52 bar
Partial pressure of Ne = (Number of moles of Ne / Total number of moles) * Total pressure
= (8.38 mol / (2.39 mol + 8.38 mol)) * 25 bar
= (8.38 mol / 10.77 mol) * 25 bar
= 19.48 bar
Therefore, the partial pressure of O2 in the gas mixture is 5.52 bar, and the partial pressure of Ne is 19.48 bar.