Help for that 1) N-N bond question and 2)for (100) niobium and 3)crystallographic direction .
Plz help me out.
question 1)
oh dear. u probably didn't understand the question. after u got the energy for N-N bond. U have to calculate lambda wavelength that too de broglie's. 0.5mv squared is the kinetic energy of the electron. So convert half mv squared to energy momentum equation. that should get u to this. P squared is equal to 2*mass of electron*Energy of the N-N bond to be broken. This P valve the momentum is substituted in the lambda formula i.e., lambda = h/P i.e., planck's constant divided by the momentum u have calculated. This should give u the answer. Try it.
KE = 1/2mv^2
and v = sqrt[(2KE)/m]
and momentum = mv = (m)x[sqrt(2KE)/m]
= msqrt[(2KE)/m] where KE is the bond energy in kJ/bond.
i juz have 1 submission left. plz juz ge mr the answer
plz bonjo n picha lite just give the answer.
cheater alert
is it possible society has degenerated to the point that it is now considered ok to cheat on exams?
do not worry too much about the slackers trying to cheat.
they never get far anyway, are identified early-on by their peers, and are denied access to employment and colleagues.
in short, loser behavior is easy to spot.