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October 30, 2014

October 30, 2014

Posted by **Sarah** on Sunday, June 2, 2013 at 11:26pm.

- To Sara: please do not multiple post the same question -
**MathMate**, Monday, June 3, 2013 at 7:04amThere are people on earth who work with 56kb Internet connections, which means that the 3 seconds that you take to make each of the quintuple posts, it could take up to 3-4 minutes for others to just to display it.

The Air America problem is a multi-step experiment, where success at each step has a probability of 86%.

We assume that the arrival of each person is independent of the others; (which is not exactly true, because the flight may have been booked for members of the same family.)

For all 15 persons to arrive independently for the flight, we calculate the probability by multiplying the probability of each of the 15 events, thus:

P(15)=0.86^15=0.1041

not exactly negligible.

- To Sarah: please do not multiple post the same question -
**MathMate**, Monday, June 3, 2013 at 7:08amSorry for having misspelled your name.

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