Posted by **Jenn** on Saturday, June 1, 2013 at 8:19pm.

women's heights are normally distributed with a mean 63.1 in and standard deviation of 2.5. A social organization for tall people has a requirement that women must be at least 69in tall. What percentage of woman meet that requirement?

The percentage of woman that are taller than 69in is __%

- Statistics -
**Anonymous**, Sunday, June 2, 2013 at 2:30am
z = (69-63.1)/ 2.5

z = 5.9/2.5

z = 2.36

- Statistics -
**Anonymous**, Sunday, June 2, 2013 at 2:33am
z = (69-63.1)/ 2.5

z = 5.9/2.5

z = 2.36

Once you have z-scores, check a z-table for the probability scores. Convert to a percentage.

## Answer This Question

## Related Questions

- statistics - Tall clubs international is a social organization for tall people. ...
- Statustics - A survey found that women’s heights are normally distributed with ...
- statistics - Assume that women's heights are normally distributed with a mean=63...
- statistics - The heights of American women aged 18 to 24 are normally ...
- statistics - The heights of American women aged 18 to 24 are normally ...
- statistics - A survey found that women's heights are normally distributed with ...
- statistics - you have requirement that men must be at least 74 in tall and women...
- statistics - Women’s heights are normally distributed with a mean of 63.6 in and...
- statistics - A survey found that women's heights are normally distributed with ...
- Statistics - Assume the heights of women are normally distributed with a mean ...

More Related Questions