Posted by Jenn on Saturday, June 1, 2013 at 8:19pm.
women's heights are normally distributed with a mean 63.1 in and standard deviation of 2.5. A social organization for tall people has a requirement that women must be at least 69in tall. What percentage of woman meet that requirement?
The percentage of woman that are taller than 69in is __%

Statistics  Anonymous, Sunday, June 2, 2013 at 2:30am
z = (6963.1)/ 2.5
z = 5.9/2.5
z = 2.36

Statistics  Anonymous, Sunday, June 2, 2013 at 2:33am
z = (6963.1)/ 2.5
z = 5.9/2.5
z = 2.36
Once you have zscores, check a ztable for the probability scores. Convert to a percentage.

Statistics  et, Friday, April 1, 2016 at 7:39pm
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