Posted by **Jenn** on Saturday, June 1, 2013 at 8:19pm.

women's heights are normally distributed with a mean 63.1 in and standard deviation of 2.5. A social organization for tall people has a requirement that women must be at least 69in tall. What percentage of woman meet that requirement?

The percentage of woman that are taller than 69in is __%

- Statistics -
**Anonymous**, Sunday, June 2, 2013 at 2:30am
z = (69-63.1)/ 2.5

z = 5.9/2.5

z = 2.36

- Statistics -
**Anonymous**, Sunday, June 2, 2013 at 2:33am
z = (69-63.1)/ 2.5

z = 5.9/2.5

z = 2.36

Once you have z-scores, check a z-table for the probability scores. Convert to a percentage.

- Statistics -
**et**, Friday, April 1, 2016 at 7:39pm
erg

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