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July 30, 2014

July 30, 2014

Posted by **Paige** on Saturday, June 1, 2013 at 6:39pm.

thanks

- Math -
**bonjo**, Saturday, June 1, 2013 at 6:46pmJoe weighs 30lbs less than 2wice kens weight

J=2x-30

ken gains 10lbs, then 2gether would weigh 250

(x+10)+J = 250

J=joe's weight.

solve them simultaneously..

hope that helps

- Math -
**Paige**, Saturday, June 1, 2013 at 6:48pmim confused can you explain a little more cause i need a full equation and im really confused

- Math -
**bonjo**, Saturday, June 1, 2013 at 7:10pmyou need to construct simultaneous equations from the information;

first equation is from; Joe weighs 30lbs less than 2wice kens weight. and x is ken's weight. so twice kens weight is 2x. 30lbs less than twice kens weight is 2x-30. these equals to Joes weight

J=2x-30 (1)

we cannot work with this equation alone because, there are two unknowns J and x. so we need another equation which is obtained from; If ken gains 10 pounds then together they would weigh 250 pounds.

i.e. if ken gains 10lbs (x+10), then together (with J) will equal to 250.

(x+10)+J = 250 (2)

Now we can solve for each weight either by substitution or elimination method..

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