Saturday
March 25, 2017

Post a New Question

Posted by on .

Joe weighs 30 lbs less than twice ken's weight. If ken gains 10 pounds then together they would weigh 250 pounds. How much does each of them weigh? let x be ken's weight.

thanks

  • Math - ,

    Joe weighs 30lbs less than 2wice kens weight
    J=2x-30

    ken gains 10lbs, then 2gether would weigh 250
    (x+10)+J = 250

    J=joe's weight.

    solve them simultaneously..

    hope that helps

  • Math - ,

    im confused can you explain a little more cause i need a full equation and im really confused

  • Math - ,

    you need to construct simultaneous equations from the information;

    first equation is from; Joe weighs 30lbs less than 2wice kens weight. and x is ken's weight. so twice kens weight is 2x. 30lbs less than twice kens weight is 2x-30. these equals to Joes weight
    J=2x-30 (1)

    we cannot work with this equation alone because, there are two unknowns J and x. so we need another equation which is obtained from; If ken gains 10 pounds then together they would weigh 250 pounds.

    i.e. if ken gains 10lbs (x+10), then together (with J) will equal to 250.
    (x+10)+J = 250 (2)

    Now we can solve for each weight either by substitution or elimination method..

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question