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December 18, 2014

December 18, 2014

Posted by **Nora 4** on Saturday, June 1, 2013 at 4:34pm.

(a) Find the probability for 0 heads.

Incorrect: Your answer is incorrect. . Your answer cannot be understood or graded. More Information Redone 0/3 was my answer

(b) Find the probability for 1 head.

Incorrect: Your answer is incorrect. . 1/3 because tossed three coins and one head

(c) Find the probability for 2 heads.

Incorrect: Your answer is incorrect. . 2/3 because tossed three coins and 2 heads

(d) Find the probability for 3 heads.

3/3 or 1 because of three coins and tossed three times...

- math answer check -
**Steve**, Saturday, June 1, 2013 at 5:03pmOn each toss, there is a 1/2 probability of a head.

(a) and (d) are the same, because p(H) = p(T) = 1/2 so 3 heads is the same as 3 tails (0 heads)

The events are independent, so P(HHH) = P(H)*P(H)*P(H) = 1/2 * 1/2 * 1/2 = 1/8

(a) and (d) are both 1/8

(b) and (c) are the same, since P(1 head) = P(1 tail) = P(2 heads)

P(1 head) = P(HTT)+P(THT)+P(TTH) = 1/8 + 1/8 + 1/8 = 3/8

or,

P(1 head) = 1 - P(all heads) - P(all tails) - P(2 heads)

But P(2 heads) = P(1 head), so

P(1 head) = (1-P(HHH)-P(TTT))/2 = (1 - 2/8)/2 = 3/8

Each specific ordering of throws has a 1/8 chance of coming up, since there are 8 possible outcomes.

If you lst the possible outcomes, you will see that 1 has all heads, 1 has all tails, and 3 have 2 of one and 1 of the other.

You should never have guessed 0/3 on (a) since there is obviously a chance for a head on every throw.

- math answer check -
**Nora 57**, Saturday, June 1, 2013 at 5:16pmI see what you are saying now, I even tossed a coin trying to figure this out. Thank you, some of these really get to me but I get some of them right off.

- math answer check -
**Steve**, Saturday, June 1, 2013 at 5:24pmTossing a coin was a good idea, but you can't control what happens. Better would have been to take three coins and line them up, then ask

what are all the possible outcomes of 3 coins in a row? and start flipping them around.

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