Post a New Question

Physics 1 College Level

posted by on .

If D = 3204 meters and d = 1247 meters in the figure, what is the magnitude of the force on the space ship to the nearest MN? Consider all three to be point masses.

I'm not even sure to begin with this question. Any help will be much appreciated!

  • Physics 1 College Level - ,

    R=sqrt(D²+d²)=sqrt(3204²+1247²)=3438 m
    The angle between R and D is
    cos α =D/R =3204/3438
    mass of the spaceship m=?
    mass of asteroid M=?
    F=2F₁cos α=…

  • Physics 1 College Level - ,

    Spaceship is 2.5 x 10^7 kg! Asteroid is 3.5 x 10^18 kg. Thanks! I'll try and figure it out and compare answers if you respond back!

Answer This Question

First Name:
School Subject:

Related Questions

More Related Questions

Post a New Question