Posted by **Devin** on Saturday, June 1, 2013 at 4:09pm.

If D = 3204 meters and d = 1247 meters in the figure, what is the magnitude of the force on the space ship to the nearest MN? Consider all three to be point masses.

I'm not even sure to begin with this question. Any help will be much appreciated!

- Physics 1 College Level -
**Elena**, Saturday, June 1, 2013 at 5:26pm
R=sqrt(D²+d²)=sqrt(3204²+1247²)=3438 m

The angle between R and D is

cos α =D/R =3204/3438

α=21.26⁰

mass of the spaceship m=?

mass of asteroid M=?

F₁=GmM/R²=…

F=2F₁cos α=…

- Physics 1 College Level -
**Devin**, Monday, June 3, 2013 at 12:57am
Spaceship is 2.5 x 10^7 kg! Asteroid is 3.5 x 10^18 kg. Thanks! I'll try and figure it out and compare answers if you respond back!

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