#1 is worded wrong, if 2 square root of 17-x = 2x-10, find the value of x/4.
#1 Can't quite parse the problem, but if
2√(17-x) = 2x-10
√(17-x) = x - 5
17-x = x^2 - 10x + 25
x^2 - 9x + 8 = 0
(x-1)(x-8) = 0
x = 1 or 8
but x=1 does not fit the original equation, so x=8, and x/4 = 2
#2 Recall that |n| = n if n>=0 and -n if n<0
if 3x+6>=0, then
3x+6 < 9
x < 1
If 3x+6 < 0,
-(3x+6) < 9
-3x - 6 < 9
-3x < 15
x > -5
so -5 < x < 1
Looks like -1 is the only choice.
Think of the graph of |x|. It is a V-shape. So, if |x| < n you get the pointy part of the v below the line y=n.
5 < |2x+1| < 11
This is just a sneaky way of getting you to solve two inequalities in one problem. You end up with
-6 < x < -3 or 2 < x < 5
Looks like -4 is the only choice.
y = k/x
8 = k/1.55
k = 12.4
so, when y = -.62
-.62 = 12.4/x
x = -20
41abc(-1 + z)-41abcz
ever heard of the distributive property?
41abc(-1) + 41abc(z) - 41abcz
-41abc + 41abcz - 41abcz
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