Posted by **Abby** on Friday, May 31, 2013 at 12:53am.

If a ball is thrown straight up into the air with an initial velocity of 95 ft/s, its height in feet after t seconds is given by

f(t)=95t−16t^2

Find the average velocity for the time period beginning when t=1 and lasting

(i) 0.5 seconds

(ii) 0.1 seconds

(iii) 0.01 seconds

(iii) 0.001 seconds

Based on the above results, guess what the instantaneous velocity of the ball is when t=1.

- Calculus -
**Steve**, Friday, May 31, 2013 at 11:01am
in each case, the average velocity is ∆y/∆x for the given interval.

So, for [1,1.5],

∆y/∆x = (f(1.5)-f(1))/(1.5-1)

= (106.5-79)/.5

= 55

Do the others similarly

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