How many moles S are required to prepare 800 liters of SO2 gas in a synthesis reaction?

To determine the number of moles of sulfur (S) required to prepare 800 liters of SO2 gas, we need to use the ideal gas law. The ideal gas law is represented by the equation:

PV = nRT

Where:
P = pressure of the gas
V = volume of the gas
n = number of moles of the gas
R = ideal gas constant (0.0821 L·atm/mol·K)
T = temperature in Kelvin

This equation allows us to calculate the number of moles of a gas if we know the volume, pressure, and temperature. However, in this case, we are given only the volume and need to find the number of moles (n). We can rearrange the ideal gas law equation to:

n = PV / RT

Now, we need to gather the necessary information to plug into the equation. The volume is given as 800 liters, and the temperature is typically assumed to be around room temperature (which is approximately 298 K). The pressure of the gas is not provided in the question, so we will assume standard pressure, which is 1 atmosphere (atm).

Now, we can calculate the number of moles of Sulfur (S) needed using this information:

n = (1 atm) * (800 L) / [(0.0821 L·atm/mol·K) * (298 K)]

By performing the calculation, we find that the number of moles of sulfur required to prepare 800 liters of SO2 gas is approximately 32.55 moles.