Posted by **ABCD** on Wednesday, May 29, 2013 at 4:28am.

Given the set of integers {1,2,3,…,801}, what is the maximum number of sets we could distribute these numbers into such that the sum of each set is exactly the same.

- Maths -
**MathMate**, Thursday, May 30, 2013 at 9:27pm
If we sum the sequence,

S=&sum i, i=1,801, we have

S=3²*89*401, as prime factorization.

Thus the largest number of groups is 401 sets, each sum would therefore be 801, as follows:

{1,800},{2,799}...{399,402},{400,401},{801} for a total of 401 sets.

## Answer This Question

## Related Questions

- Mathematics - Given the set of integers {1,2,3,…,801}, what is the maximum ...
- maths - The numbers 1,2,…,17 are divided into 5 disjoint sets. One set has 5 ...
- mathematics - The numbers 1,2,…,17 are divided into 5 disjoint sets. One set has...
- Algerba II - Hi Do decimals such as 2.718 represent rational numbers or ...
- algebra - What set of numbers is described by M={1, 2, 3, 7} L={3, 7, 9} a) {3,7...
- SAT prep help - Set M consists of the consecutive integers from -15 to y, ...
- calculus - what is the property that distinguishes finite sets from infinite ...
- MATH - A set of numbers has “the triple-sum property” (or TSP) if there exist ...
- SAT math - Set M consists of the consecutive integers from -15 to y, inclusive. ...
- maths - explain why are the following not groups: 1)the set of Z integers with ...

More Related Questions