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July 31, 2014

July 31, 2014

Posted by **steven** on Tuesday, May 28, 2013 at 5:30pm.

f'(x) = x sqrt 16 − x^2

.

f(x) =

- math calculus -
**Reiny**, Tuesday, May 28, 2013 at 8:49pmDid you mean

f'(x) = x√(16-x^2) ??? , brackets are needed here.

then f(x) = (-1/3)(16 - x^2)^(3/2) + c

(differentiate to confirm)

if x = 4/3 , f(4/3) = 0

0 = (-1/3)(16 - 16/9)^(3/2) + c

solve for c and sub back into f(x) =

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