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November 27, 2014

November 27, 2014

Posted by **Anonymous** on Monday, May 27, 2013 at 7:29pm.

- Pre-Cal -
**Anonymous**, Monday, May 27, 2013 at 7:31pm"e thing" above is supposed to be "theta"

and theta=-2 is a polar equation

- Pre-Cal -
**Steve**, Tuesday, May 28, 2013 at 11:06amθ = -2

This is just a straight line, along the angle θ=-2.

Recall that the slope of the line: tanθ = sinθ/cosθ = rsinθ/rcosθ = y/x

So, y/x = tan(-2) = 2.185

y = 2.185x

Makes sense, since θ is in QIII, so the line slopes up from the left.

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