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November 28, 2014

November 28, 2014

Posted by **Saif** on Monday, May 27, 2013 at 1:24pm.

- Math -
**MathMate**, Monday, May 27, 2013 at 6:45pmSolve for t in d(t)=25 and d(t)=0, where d(t) is given as:

d(t)= -5t^2 + 10t + 20

we find that d(1)=25, and d(3.23)=0.

Note: not sure if the diver was on earth. The acceleration due to gravity is only 10 instead of 32.2 f/s2 unless the distance d is in metres.

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