Posted by Davey on .
Find the area between the two curves y1= x^2  4x + 5 and y2 = 2x  3, finding the points of intersection algebraically.

Calculus 
Reiny,
intersection points:
x^2  4x + 5 = 2x3
x^2  6x + 8 = 0
(x2)(x4) = 0
x = 2 or x = 4
in that domain, the effective height of the region is
2x3  (x^24x+5) = x^2 + 6x  8
area of region
= ∫(x^2 + 6x  8) dx from x = 2 to x = 4
= [ x^3/3 + 3x^2  8x] from 2 to 3
= 9 + 27  24  (8/3 + 12  16)
= 2/3
check my arithmetic