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March 31, 2015

March 31, 2015

Posted by **Anonymous** on Sunday, May 26, 2013 at 5:15pm.

- statistics -
**MathMate**, Sunday, May 26, 2013 at 5:25pmAssume

There are

N=10C5 ways of randomly choosing 5 horses out of 10.

where

N=10!/(5!5!)=25

We assume that

1. order does not count,

2. winning probabilities are equal among horses,

3. results are completely random.

Then the owner has one chance in 252 that his 5 horses are placed 1st to 5th.

- statistics- correction -
**MathMate**, Sunday, May 26, 2013 at 5:26pmN=10C5=10!/(5!5!)=252

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