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July 23, 2014

July 23, 2014

Posted by **Ayanda** on Sunday, May 26, 2013 at 10:16am.

1.The kineyic energy of the vehicle after 2 minutes

2.The potential energy of the vehicle after 2 minutes

- Engineering science -
**MathMate**, Sunday, May 26, 2013 at 10:48amHints:

Kinetic energy,

KE=(1/2)mv²

where

m=mass of object (kg)

v=velocity (m/s)

Potential energy

=mgh

m=mass in kg

g=acceleration due to gravity, m/s^{-2}

h=height above datum in m.

To calculate h, you need the distance travelled.

For uniform acceleration, distance d, is the average speed (72 km/h ÷ 2, converted to m/s) multiplied by the time (2 minutes, converted to seconds).

The height, h is then

h=d*slope = d/25 (for a 1/25 slope)

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