1) 3x(4x-9)= 12x^2-27x
2) 4x^2(x+6)=
3) 2x^2(15x^3-10)
Use the same method as you used in the first problem.
2= 5x^2+24x^2
? i don't understand
1) To solve the equation 3x(4x-9) = 12x^2-27x, we need to simplify each side of the equation first and then solve for the variable x.
First, distribute the 3x to the terms inside the parentheses:
3x * 4x = 12x^2
3x * -9 = -27x
Now, the equation becomes:
12x^2 - 27x = 12x^2 - 27x
Since the terms on both sides of the equation are identical, the equation is true for all values of x. So, there are infinitely many solutions for x in this case.
2) To solve the equation 4x^2(x+6), there is no equal sign present, so it is not a complete equation. It looks like an expression that can be simplified, but it cannot be solved for a specific value of x without an equal sign.
If you meant to write 4x^2(x+6) = 0, then we could solve it by factoring. Setting each factor equal to zero provides potential solutions:
4x^2 = 0 or (x + 6) = 0
Solving the first factor:
4x^2 = 0
Divide both sides by 4: x^2 = 0
Take the square root of both sides: x = 0
Solving the second factor:
(x + 6) = 0
Subtract 6 from both sides: x = -6
Therefore, the solutions for the equation 4x^2(x+6) = 0 are x = 0 and x = -6.
3) To simplify the expression 2x^2(15x^3-10), you need to distribute 2x^2 to the terms inside the parentheses:
2x^2 * 15x^3 = 30x^5
2x^2 * -10 = -20x^2
Now, the expression becomes:
30x^5 - 20x^2
This is the simplified form of the given expression.