Edna has scored in 80% of the games she's played.What is the probability she woulds score a goal in at least 7 out of her 8 games. P (if she scored in 3 or 4 games, what is the probability that she scores in exactly 4).?

p=probability of scoring (success) = 0.8

q=probability of not scoring (failure = 0.2

Assuming the probability does not change over time and is independent of previous results, then we can apply the binomial distribution:
P(7+ out of 8)
=8C7*0.8^70.2+8C80.8^8
=0.34+.17
=0.50 (approx.)

Please explain the part of the question in parentheses... "scored in 3 or 4 games..." How many did she play?