Posted by **Andy** on Friday, May 24, 2013 at 4:18pm.

f(x)is a function differentiable at x=1 and f'(1)=1/8.

what is the value of f(x)-f(1)

f'(x) denotes the derivative of f(x)

- Maths -
**MathMate**, Friday, May 24, 2013 at 7:35pm
For x *near* 1, you can use linearlization, which is

f(x)=f'(1)(x-1)+f(1)

=(1/8)x+f(1)

Therefore, within the errors of the linearization,

f(x)-f(1) = (x-1)/8 (approximately)

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