There is a jar of 16 marbles. 4 red, 7 blue and 5 green. 1) What is the probability of selecting a red marble, REPLACING it, and then selecting a blue marble.
2) What is the probability of selecting a red marble, then SETTING IT ASIDEm then selecting a blue marble?
1) 4/16 * 7/16
2) 4/16 * 7/15
To find the probability of selecting marbles with replacement and without replacement, we need to determine the total number of marbles and the number of marbles in each desired outcome.
1) Probability of selecting a red marble, REPLACING it, and then selecting a blue marble:
Step 1: Find the total number of marbles in the jar: 16 marbles
Step 2: Determine the probability of selecting a red marble: 4 red marbles out of 16 total marbles = 4/16 = 1/4
Step 3: Since we are replacing the red marble back into the jar, the probability of selecting a blue marble remains the same.
Step 4: Determine the probability of selecting a blue marble: 7 blue marbles out of 16 total marbles = 7/16
Step 5: Multiply the probabilities together to get the overall probability:
Probability of selecting a red marble and then a blue marble = (1/4) * (7/16) = 7/64
Therefore, the probability of selecting a red marble, replacing it, and then selecting a blue marble is 7/64.
2) Probability of selecting a red marble, SETTING IT ASIDE, and then selecting a blue marble:
Step 1: Find the total number of marbles in the jar: 16 marbles
Step 2: Determine the probability of selecting a red marble: 4 red marbles out of 16 total marbles = 4/16 = 1/4
Step 3: After selecting the red marble, set it aside. So the total number of marbles in the jar for the second pick is reduced by 1.
Step 4: Determine the probability of selecting a blue marble from the reduced jar: 7 blue marbles out of 15 remaining marbles = 7/15
Step 5: Multiply the probabilities together:
Probability of selecting a red marble and then a blue marble = (1/4) * (7/15) = 7/60
Therefore, the probability of selecting a red marble, setting it aside, and then selecting a blue marble is 7/60.