Posted by **Mathslover** on Friday, May 24, 2013 at 1:48am.

The sequence {ak}112 (base)k=1 satisfies a1=1 and an=1337+n/an−1, for all positive integers n. Let

S=⌊a10a13+a11a14+a12a15+⋯+a109a112⌋.

Find the remainder when S is divided by 1000.

Details and assumptions

The function ⌊x⌋:R→Z refers to the greatest integer smaller than or equal to x. For example ⌊2.3⌋=2 and ⌊−5⌋=−5.

## Answer This Question

## Related Questions

- MATHS - The sequence {ak}112,k=1 satisfies a1=1 and an=1337+n/an−1, for ...
- maths - A subset S of {1,2,…,n} is said to be packed if whenever i,j∈S the...
- heeeeeeeeelp math - A subset S of {1,2,…,n} is said to be packed if whenever i,j...
- heeeeeelp math - A subset S of {1,2,…,n} is said to be packed if whenever i,j&#...
- cananyone solvethis math - A subset S of {1,2,…,n} is said to be packed if ...
- Combinations Maths - For how many positive integers n are there exactly ⌊n...
- math - how can we make numbers from 1 to 15 with three 2? (you can make this ...
- Math (number theory) - For how many positive integers N is ⌊N^2/5⌋(...
- Algebra - How many positive integers are there such that ⌊√x⌋=...
- Calculus - PLEASE HELP!! - For any real number x there is a unique integer n ...

More Related Questions