Posted by **SOmebody** on Thursday, May 23, 2013 at 11:23pm.

The sequence {ak}112,k=1 satisfies a1=1 and an=1337+n/an−1, for all positive integers n. Let

S=⌊a10a13+a11a14+a12a15+⋯+a109a112⌋.

Find the remainder when S is divided by 1000.

- MATHS -
**rajeev bhatt**, Saturday, May 25, 2013 at 10:36am
849

- MATHS -
**K**, Saturday, May 25, 2013 at 10:11pm
explain, please?

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