Determine the mass of 100mL of vinegar if the density of vinegar is 1.09 g/mol
I'm sure you made a typo and your post should have read........1.09 g/mL.
1.09 g/mL x 100 mL = ? grams.
To determine the mass of 100mL of vinegar, we need to use its density. Density is defined as mass per unit volume. In this case, the density of vinegar is given as 1.09 g/mol.
To calculate the mass of 100mL of vinegar, we need to consider two things:
1. The volume of vinegar (100mL)
2. The density of vinegar (1.09 g/mol)
The density of vinegar is given in grams per mole (g/mol), which implies that 1 mole of vinegar occupies 1.09 grams. However, we are interested in finding the mass of 100mL of vinegar, not the mass of 1 mole.
To find the mass of 100mL of vinegar, we need to convert mL to moles and then moles to grams.
First, we need to convert 100mL to liters since density is typically given in grams per milliliter (g/mL) or grams per cubic centimeter (g/cm³).
1 liter is equal to 1000 mL, so 100mL is equal to 0.1 liters.
Now, we can calculate the volume in moles using the density:
Density (g/mol) = Mass (g) / Volume (L)
Rearranging the equation:
Mass (g) = Density (g/mol) * Volume (L)
Mass (g) = 1.09 g/mol * 0.1 L
Mass (g) = 0.109 g
Therefore, the mass of 100mL of vinegar is 0.109 grams.