Thursday

July 31, 2014

July 31, 2014

Posted by **manpreet** on Thursday, May 23, 2013 at 7:26pm.

- maths -
**Steve**, Friday, May 24, 2013 at 11:17am(1+sinθ)/(1-sinθ)

= (1+sinθ)/(1-sinθ) * (1+sinθ)/(1+sinθ)

= (1+sinθ)^2 / (1-sin^2θ)

= (1+2sinθ+sin^2θ)/cos^2θ

= sec^2θ + 2secθtanθ + tan^2θ

= (secθ+tanθ)^2

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