Posted by **bubbie** on Thursday, May 23, 2013 at 6:13pm.

A locker combination has four nonzero digits. If no digit can be repeated and the first three digits are 1-2-3, what is the probability that the fourth digit is 4?

A. 1/6

B. 1/7

C. 1/8

D. 1/9

- Maths -
**bubbie**, Thursday, May 23, 2013 at 6:17pm
i am confused about this problem and would like some help. thank you x.x

- Maths -
**Ms. Sue**, Thursday, May 23, 2013 at 6:22pm
Since the combination has already used 1, 2, and 3. Then the 4th digit must be either 4, 5, 6, 7, 8, or 9.

So the probability must 1 out of 6 or 1/6.

- Maths -
**bubbie**, Thursday, May 23, 2013 at 6:25pm
thank you, ms. sue! that's what i thought it was but i was confused. :)

- Maths (incomplete) -
**PsyDAG**, Thursday, May 23, 2013 at 6:26pm
With your data, I am confused too. How many total numbers are there?

Since the first 3 numbers cannot be repeated, the answer = 1/(total-3)

- Maths -
**Ms. Sue**, Thursday, May 23, 2013 at 6:29pm
You're welcome, bubbie.

- Maths -
**bubbie**, Thursday, May 23, 2013 at 6:31pm
nonzero digits = 1-9

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