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November 26, 2014

November 26, 2014

Posted by **Mike Jones** on Wednesday, May 22, 2013 at 10:44pm.

THANK YOU VERY MUCH!!!!

- PHYSICS FINAL (orbital) -
**drwls**, Thursday, May 23, 2013 at 2:25amThe satellite's mass doesn't matter.

You will need to use the fact that the Earth's radius is 6371 km. The satellite is therefore 9921 km from the Earth's center. The value of the acceleration of gravity (g') there is

g' = g*(6371/9921)^2 = 4.046 m/s^2

where g = 9.81 m/s^2 is the value of the acceleration at the Earth's surface.

You can get the velocity V by using

V^2/R = g'

V = 6335 m/s

The period P of the satellite is given by

V*P = 2*pi*R

P = 9840 s = 2.73 hours

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