An electromagnet has a steel core (κM≈ 2500) with an approximately circular cross sectional area of 7.0 cm2. The radius of the magnet is 12.0 cm; there is a small air gap of only 2.2 mm (see sketch). The current through the magnet's N= 120-turn coil is 24 A.
What will the magnetic field strength be inside the air gap? Express your answer in Tesla. Assume that the magnetic field is azimuthal (i.e. points around the circle formed by the steel) everywhere and d≪ the radius of the electromagnet.
ans=1.44
for people with other values use this
B=(meu not*N*I)/((2*pi*R/km) +d)
Thanx hmmmm, Other problems? (1,2,3,5 & 6)
Problem 3:
a)
r = 0
theta = 0
k = (Q_0*(1+2*T/T)) / (Pi*R^2*epsilon_0)
b)
r = 0
theta = mu_0*I*r/(2*Pi*R^2)
k = 0
c)
r = - 1/mu_0 * E X B <- note the sign.
theta = 0
k = 0
d), e) -Q*I*D/(Pi*R^2*epsilon_0)
Note that Q = Q_0*(1+2T/T) and I = dQ/dt
Thanks, ^_ ^
What about probs. 1, 2 and 5 ?
Can somebody tell me what the value of R is?
thanks
VAlue of I please
Is I = radius(a)/distance(d)?
the parentheses are confusing me for (Q_0*(1+2*T/T))
WHat is value of R please?
cannot figure out.
Please tell what the value for R is?
Is I = radius(a)/distance(d)?