integral calculus
posted by help pls on .
integral of sin(x^2) dx
i actually got the ans, but aftr differentiating the answer i am not getting back the question

let u=x^2
du= 2x dx
dx=du/2x
dx=du/2sqrt(u)
1/4 cos u is the integral 
http://www.numberempire.com/integralcalculator.php
This involves the error function, not an elementary problem. Hannah has made an error. 
I'm sorry about that. Can you explain why there is an error Mr. Pursley? I genuinely don't understand how there is an error.

Your substitutions are good, but you dropped something. You should have watched the details:
∫sin(x^2) dx = ∫sin(u) / 2√u du 
then how do we proceed ??
is their any solution to this problem?