Posted by **help pls ** on Wednesday, May 22, 2013 at 8:01am.

integral of sin(x^2) dx

i actually got the ans, but aftr differentiating the answer i am not getting back the question

- integral calculus -
**Hannah**, Wednesday, May 22, 2013 at 8:25am
let u=x^2

du= 2x dx

dx=du/2x

dx=du/2sqrt(u)

-1/4 cos u is the integral

- integral calculus -
**bobpursley**, Wednesday, May 22, 2013 at 9:05am
http://www.numberempire.com/integralcalculator.php

This involves the error function, not an elementary problem. Hannah has made an error.

- integral calculus -
**Hannah**, Wednesday, May 22, 2013 at 9:09am
I'm sorry about that. Can you explain why there is an error Mr. Pursley? I genuinely don't understand how there is an error.

- integral calculus -
**Steve**, Wednesday, May 22, 2013 at 10:28am
Your substitutions are good, but you dropped something. You should have watched the details:

∫sin(x^2) dx = ∫sin(u) / 2√u du

- integral calculus -
**help pls **, Wednesday, May 22, 2013 at 10:04pm
then how do we proceed ??

is their any solution to this problem?

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