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physics

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If a metal wire carries a current of 79
.
0 mA,
how long does it take for 7.90
×
10
20
electrons
to pass a given cross-sectional area anywhere
along the wire? The fundamental charge is
1
.
602
×
10

19
C.
Answer in units of s

  • physics -

    1 amp=1coulomb/sec=1coulomb/e electrons per second
    1amp=1/1.603E-19 electrons/sec

    = 6.24E18 electrons per second.

    so then 79ma=.079amp=.079*6.24E18 electrons/sec

    time=electcrons/rate=7.90E20/.079*6.24E18

    time=1603seconds

    check all that

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