Chad buys peanuts in 2 pound bags. He repackages them into bags that hold 5/6 pound of peanuts. How many 2 pound bags of peanuts should Chad buy so that he can fill the 5/6 pound bags without having any peanuts left over?
What are the steps to find the answer.
For each 2 pound bag, two bags can be filled (5/6) leaving 2/6 remaining. Using the remainders, 10/6 would leave no peanuts left over. Can you work it from here?
You can use the minimal amount for this problem or any multiple of the minimal amount.
To find out how many 2-pound bags Chad should buy, we need to divide the weight of the 2-pound bags by the weight of each 5/6 pound bag.
Step 1: Convert the weight of each bag to a common unit. Since the 2-pound bags are already in pounds, we need to convert the weight of the 5/6 pound bag to pounds as well. To do this, we multiply the numerator (5) by the reciprocal of the denominator (6), which gives us (5/6) * (1/1) = 5/6 pounds.
Step 2: Divide the weight of the 2-pound bag by the weight of each 5/6 pound bag to find the number of 2-pound bags needed. So, we divide 2 pounds by 5/6 pounds.
On dividing 2 by 5/6, we multiply 2 by the reciprocal of 5/6: 2 * (6/5) = 12/5.
Step 3: Simplify the resulting fraction. The fraction 12/5 can be simplified to a mixed number (a whole number and a fraction). Dividing 12 by 5 gives us a quotient of 2 with a remainder of 2, so the result is 2 and 2/5.
Therefore, Chad should buy 2 and 2/5 (or 2.4) 2-pound bags of peanuts to fill the 5/6 pound bags without any leftovers.