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April 1, 2015

April 1, 2015

Posted by **Ressie** on Tuesday, May 21, 2013 at 5:12pm.

A model rocket is launched from the ground with an initial speed of 50 feet per second. The equation that models its height, h feet, off the ground t seconds after it was fired is

h=-16ft^2+50t

a)How high is the rocket 1 seconds after it was fired?

b)How long will it take the rocket to return to earth?

- algebra -
**henry**, Thursday, May 23, 2013 at 2:41pma. h = 50*1 - 16*1^2 = 34 Ft.

b. V = Vo + g*t

Tr = (V-Vo)/g = (0-50)/-32 = 1.56 s. =

Rise time.

Tf = Tr = 1.56 s. = Fall time.

T = Tr + Tf = 1.56 + 1.56 = 3.125 s. =

Time t0 return to earth.

t

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