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Posted by on Tuesday, May 21, 2013 at 5:12pm.

The question I have is to solve the problem.
A model rocket is launched from the ground with an initial speed of 50 feet per second. The equation that models its height, h feet, off the ground t seconds after it was fired is
h=-16ft^2+50t
a)How high is the rocket 1 seconds after it was fired?
b)How long will it take the rocket to return to earth?

  • algebra - , Thursday, May 23, 2013 at 2:41pm

    a. h = 50*1 - 16*1^2 = 34 Ft.

    b. V = Vo + g*t
    Tr = (V-Vo)/g = (0-50)/-32 = 1.56 s. =
    Rise time.
    Tf = Tr = 1.56 s. = Fall time.

    T = Tr + Tf = 1.56 + 1.56 = 3.125 s. =
    Time t0 return to earth.
























    t

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