Posted by **Sammy** on Tuesday, May 21, 2013 at 4:08pm.

The Ferris wheel at a carnival has a diameter of 18m and descends to 2m above the

ground at its lowest point. Assume that a rider enters a car at this point and rides the wheel

for two revolutions

My main problem is how to get the phase shift. (The answer says its 270 degrees)

- Trigonometric Functions! (Ferris Wheel) -
**Steve**, Tuesday, May 21, 2013 at 4:18pm
well, since sin(x) has a max at x=90, and a min at x=270, that phase shift makes sense. You will have something along the lines of

sin(x+270)

The radius of the wheel is 9, and the whole wheel is lifted 2m, so we have

9sin(x+270)+11

see, at x=0, y=9(-1)+11 = 2

at x=90, y=9(0)+11 = 11

and so on

- Trigonometric Functions! (Ferris Wheel) -
**Sammy**, Tuesday, May 21, 2013 at 4:46pm
Thank you very much Steve!

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