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March 30, 2017

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The Ferris wheel at a carnival has a diameter of 18m and descends to 2m above the
ground at its lowest point. Assume that a rider enters a car at this point and rides the wheel
for two revolutions

My main problem is how to get the phase shift. (The answer says its 270 degrees)

  • Trigonometric Functions! (Ferris Wheel) - ,

    well, since sin(x) has a max at x=90, and a min at x=270, that phase shift makes sense. You will have something along the lines of

    sin(x+270)

    The radius of the wheel is 9, and the whole wheel is lifted 2m, so we have

    9sin(x+270)+11

    see, at x=0, y=9(-1)+11 = 2
    at x=90, y=9(0)+11 = 11
    and so on

  • Trigonometric Functions! (Ferris Wheel) - ,

    Thank you very much Steve!

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