Calculate the grammes of oxygen which would involved on heating 5g of potassium trioxochlorate(v)
To calculate the number of grams of oxygen involved in the heating of 5g of potassium trioxochlorate(V) (KClO3), we first need to know the balanced chemical equation for the reaction.
The balanced chemical equation for the decomposition of potassium trioxochlorate(V) is:
2 KClO3 -> 2 KCl + 3 O2
From the balanced equation, we can see that for every 2 moles of KClO3, we get 3 moles of O2.
To calculate the amount of oxygen in grams, we need to follow these steps:
Step 1: Convert the given mass of KClO3 to moles.
Use the molar mass of KClO3 to convert grams to moles.
The molar mass of KClO3 is calculated as:
K (39.1 g/mol) + Cl (35.5 g/mol) + 3 O (16.0 g/mol) = 122.55 g/mol
So, 5 g KClO3 = (5 g) / (122.55 g/mol) = 0.0408 mol KClO3
Step 2: Use the mole ratio from the balanced equation to find the moles of O2.
From the balanced equation, we know that for every 2 moles of KClO3, we have 3 moles of O2.
Thus, 0.0408 mol KClO3 * (3 mol O2 / 2 mol KClO3) = 0.0612 mol O2
Step 3: Convert the moles of O2 to grams.
Use the molar mass of O2 to convert moles to grams.
The molar mass of O2 is calculated as:
2 O (16.0 g/mol) = 32.0 g/mol
So, 0.0612 mol O2 = (0.0612 mol) * (32.0 g/mol) = 1.96 g O2
Therefore, heating 5g of potassium trioxochlorate(V) will produce 1.96 grams of oxygen.