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Posted by on Tuesday, May 21, 2013 at 10:02am.

f(x) is a cubic polynomial that satisfies f(1)=f(2)=f(3)=4 and f(0)=0. What is the value of f(7)?

  • Math (Algebra) - , Tuesday, May 21, 2013 at 11:01am

    f(x) = ax^3 + bx^2 + cx

    a+b+c = 4
    8a+4b+2c = 4
    27a+9b+3c = 4

    f(x) = 2x/3 (x^2 - 6x + 11)

    f(7) = 84

  • Math (Algebra) - , Tuesday, May 21, 2013 at 11:07am

    Thanks Steve!

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