Posted by **Mat** on Tuesday, May 21, 2013 at 9:38am.

Find the area of the region between the parabola 4y = x^2 and the line 3x + 4 y = 4

- calculus -
**Steve**, Tuesday, May 21, 2013 at 11:05am
The curves intersect at (-4,4) and (1,1/4)

So, just integrate to find

a = ∫[-4,1] (4-3x)/4 - x^2/4 dx

a = 125/24

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