Posted by Mat on .
Find the area of the region between the parabola 4y = x^2 and the line 3x + 4 y = 4

calculus 
Steve,
The curves intersect at (4,4) and (1,1/4)
So, just integrate to find
a = ∫[4,1] (43x)/4  x^2/4 dx
a = 125/24