Post a New Question

math

posted by on .

Dave walked from point A to point B due North East for a distance of 20m. He immediately changed direction and walked 50m from B to C on a bearing of 110 degrees.

i. Calculate the distance AC
ii. Find the bearing of C from A

  • math - ,

    1. d = 20m[45o] + 50m[110o]

    X = 20*cos45 + 50*cos110 = -2.96 m.
    Y = 20*sin45 + 50*sin110 = 61.1 m.

    tanAr = Y/X = 61.1/-2.96 = -20.64189
    Ar = -87.23o = Reference angle.
    A = -87.23 + 180 = 92.8o

    d = Y/sinA = 61.1/sin92.8 = 61.2 m.= AC.

    2. Bearing = 92.8-90 = 2.8o West of North.

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question