Tuesday

July 29, 2014

July 29, 2014

Posted by **Dan** on Tuesday, May 21, 2013 at 1:34am.

- Math (Algebra) -
**Steve**, Tuesday, May 21, 2013 at 12:11pmIf the coefficients are all rational, then the irrational roots must occur in conjugate pairs. So, the polynomial is

(x-(√2+√3+√5))

(x-(√2+√3-√5))

(x-(√2-√3+√5))

(x-(√2-√3-√5))

(x-(-√2+√3+√5))

(x-(-√2+√3-√5))

(x-(-√2-√3+√5))

(x-(-√2-√3-√5))

x^8 - 40x^6 + 352x^4 - 960x^2 + 576

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