CHEMPLEASE HELP
posted by JOJO on .
1 Calculate the equilibrium concentration for H+, HSO4 and SO4^2 , given a .150M H2SO4 solution. the Ka for HSO4 is 1.20*10^2

The first ionization is 100%; therefore,
..........H2SO4 ==> H^+ + HSO4^
I.........0.150......0.....0
C........0.l50...0.150..0.150
The second H is weak.
............HSO4^ ==> H^+ + SO4^2
I.........0.150......0.150..0
C...........x.........+x...x
E........0.150x....0.150+x..x
k2 = 0.012 = (H^+)(SO4^2)/(HSO4^)
Substitute the E line of the second ICE chart and solve for x, then
total (H^+) = 0.150+x
(SO4^2) = x
(HSO4^) = 0.150x
Of course (H2SO4) = 0