Posted by **JOJO** on Monday, May 20, 2013 at 6:51pm.

1- Calculate the equilibrium concentration for H+, HSO4- and SO4^2- , given a .150M H2SO4 solution. the Ka for HSO4- is 1.20*10^-2

- CHEM-PLEASE HELP -
**DrBob222**, Monday, May 20, 2013 at 9:33pm
The first ionization is 100%; therefore,

..........H2SO4 ==> H^+ + HSO4^-

I.........0.150......0.....0

C........-0.l50...0.150..0.150

The second H is weak.

............HSO4^- ==> H^+ + SO4^2-

I.........0.150......0.150..0

C...........-x.........+x...x

E........0.150-x....0.150+x..x

k2 = 0.012 = (H^+)(SO4^2-)/(HSO4^-)

Substitute the E line of the second ICE chart and solve for x, then

total (H^+) = 0.150+x

(SO4^2-) = x

(HSO4^-) = 0.150-x

Of course (H2SO4) = 0

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