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January 31, 2015

January 31, 2015

Posted by **adam** on Monday, May 20, 2013 at 4:09pm.

- Ms Sue help -
**adam**, Monday, May 20, 2013 at 4:14pmAn anchor holding a boat stationary on a river forms a 65 degree angle with the river bottom. The anchor line is 40 meters long. Assuming the river has a uniform depth, how deep is the river directly below the boat?

- Mathematics Ms Sue help -
**adam**, Monday, May 20, 2013 at 4:15pmsorry for the repost. thanks for all your help you provide everybody on the daily

- Mathematics Ms Sue help -
**Reiny**, Monday, May 20, 2013 at 4:20pmIf you look at your diagram, you should see a right-angled triangle, with base angle 88°, opposite = ? = height

and adjacent = 15 m

so height/15 = tan88

height = 15tan88 = appr 429.5m

- Mathematics Ms Sue help -
**Steve**, Monday, May 20, 2013 at 4:21pmfor the building,

h/18 = tan 88°

for the boat,

d/40 = sin 65°

for stuff like this, it always helps to draw a diagram, then dig into your box of trig ratios

- Mathematics Ms Sue help -
**Reiny**, Monday, May 20, 2013 at 4:22pmFor you second question...

this time you know the hypotenuse and the opposite side, so you know you must dealing with the sine ration

sin 65 = height/40

height = 40sin65 = appr 36.25 m

- Mathematics Ms Sue help -
**adam**, Monday, May 20, 2013 at 4:25pmthanks for all you guys helps. drawing shows a better concept then straight digging it thanks

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