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July 30, 2015

July 30, 2015

Posted by **David** on Sunday, May 19, 2013 at 8:59am.

Show that tan=a/b

- math -
**MathMate**, Sunday, May 19, 2013 at 10:28ama^3=1/cos-cos = (1-cos^2)/cos=sin^2/cos

b^3=1/sin-sin = (1-sin^2)/sin=cos^2/sin

a^3/b^3=sin^2/cos * cos^2/sin=sin^3/cos^3

=>

a/b=sin/cos = tan

(Hope you understand your own notations.)