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September 1, 2014

September 1, 2014

Posted by **ramesh reddy** on Sunday, May 19, 2013 at 7:57am.

- maths -
**Reiny**, Sunday, May 19, 2013 at 8:32amI noticed, looking at the "Related Questions" below, that you have posted this same question 3 times

The reason you are not getting any answers is that you don't have enough information.

We know nothing about the second rhombus.

BTW, the area of similar shapes is proportional to the square of their corresponding sides

you can find the side of the first:

Draw the diagonal BD, cutting the area in half

so triangle ABD = 12

area = (1/2)(a)(b)sinØ , where a and b are two sides with Ø the contained angle.

(1/2)(x)(x)sin60 = 12

x^2 (√3/2) = 24

x^2 = 48/√3

x = √ (48/√3 ) = 4√3/(√(√3) ) = appr 5.264

- maths -
**ramesh reddy**, Sunday, May 19, 2013 at 8:49amThank you Reiny .I have a doubt ,i.e.,as they have already given the two rhombus'es are similar ,can we write that the area of rhombus BFDE is also equal to rhombus ABCD?

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